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SSC GD 2024 PYQ — Question 42

SSC GD Const (English) - 20 Feb 2024 - Shift 3 • Quantitative Aptitude • Q42

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What is the value of 16×(9+4)−13×1450−(12+12)\frac{16\times(9+4)-13\times14}{50-(12+12)}?

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Correct answer: A

Explanation

The correct answer is option 1 i.e. 1.

16×(9+4)−13×1450−(12+12)\frac{16\times(9+4)-13\times14}{50-(12+12)}

⇒ (16 × 13 - 13 ×  14)/(50 - 24)

⇒ (208 - 182) / 26

⇒ 26/26 = 1