What is the value of [1 – sin (90° – 2A)]/[1 + sin (90° + 2A)]?
Show answer & explanation
Correct answer: C
Explanation
The correct answer is option 3 i.e. tan2A
[1 – sin (90° – 2A)]/[1 + sin (90° + 2A)]
= (1 - cos2A)/(1 + cos 2A)
= 1 - (1 - 2sin2A)/(1 + 2cos2A - 1)
= 2sin2A/2cos2A = tan2A