The correct answer is option 1 i.e. 1
= (1 + cotA + tanA )(sinA - cosA)(sin3A−cos3AsinAcosA)
= (1 + cotA + tanA )(sinA - cosA) ((sinA−cosA)(1+sinAcosA)sinAcosA)
= (1 + cosA/sinA + sinA/cosA)(1+sinAcosA)sinAcosA
= (sinAcosA(sin2A+cos2A+sinAcosA))((1+sinAcosA)sinAcosA)
= 1