SSC CHSL 2021 PYQ — Question 67

SSC CHSL - 15 April 2021 - Shift 2 • Quantitative Aptitude • Q67

What is the value of : [19÷19of19]×1919+19of19?\frac{{\left[ {\frac{1}{9} \div \frac{1}{9}of\frac{1}{9}} \right] \times \frac{1}{9}}}{{\frac{1}{9} + \frac{1}{9}of\frac{1}{9}}}?

Show answer & explanation

Correct answer: D

Explanation

The correct answer is option 4 i.e.  8110\frac{1}{10}

Evaluate using the BODMAS rule which says, 'Brackets, Order, Division, Multiplication, Addition, Subtraction'

[19÷19of19]×1919+19of19?\frac{{\left[ {\frac{1}{9} \div \frac{1}{9}of\frac{1}{9}} \right] \times \frac{1}{9}}}{{\frac{1}{9} + \frac{1}{9}of\frac{1}{9}}}?

=[19×91×19]×1919+19×19\frac{{\left[ {\frac{1}{9} \times \frac{9}{1}\times\frac{1}{9}} \right] \times \frac{1}{9}}}{{\frac{1}{9} + \frac{1}{9}\times\frac{1}{9}}}

=19 ×1919+19×19\frac{{{\frac{1}{9} } \ \times \frac{1}{9}}}{{\frac{1}{9} + \frac{1}{9}\times\frac{1}{9}}}

= 8110\frac{1}{10}