SSC MTS 2023 PYQ — Question 12

The correct answer is option 3 i.e. $\frac{59}{40}$

Given that

  the value of $\frac{1}{2}$of$\frac{16}{5}$+$\frac{1}{8}$of $\frac{24}{9}$x $\frac{18}{12}$ -- $\frac{5}{8}$ 

⇒  $\frac{1}{2}$of$\frac{16}{5}$+$\frac{1}{8}$of $\frac{24}{9}$x $\frac{18}{12}$ -- $\frac{5}{8}$ 

⇒ ( $\frac{1}{2}$×$\frac{16}{5}$) + ($\frac{1}{8}$ x $\frac{24}{9}$) x $\frac{18}{12}$ -- $\frac{5}{8}$ 

⇒  $\frac{16}{10}$ + $\frac{1}{3}$ x $\frac{18}{12}$ -- $\frac{5}{8}$ 

⇒  $\frac{8}{5}$ + $\frac{1}{2}$ -- $\frac{5}{8}$ 

⇒  $\frac{21}{10}$ -- $\frac{5}{8}$ 

⇒  $\frac{84 - 25}{40}$

⇒ $\frac{59}{40}$