What is the sum of digits of the least number which when divided by 21, 28, 30 and 35 leaves the same remainder 10 in each case but is divisible by 17?
Show answer & explanation
Correct answer: B
Explanation
The correct answer is option 2 i.e. 13
the least number which when divided by 21, 28, 30 and 35 leaves the same remainder 10 is LCM of 21, 28, 30, 35 + 10
⇒ 420 + 10 = 430
In other case it should also be divisible by 17 Hence 420k + 10 should be divisible by 17
On putting k = 2 Number becomes 420 × 2 + 10 = 850 it is also divisible by 17
Hence sum of digits = 8 + 5 + 0 = 13