What is the smallest number which when divided by 64 and 80 leaves remainder 9 in each case?
Show answer & explanation
Correct answer: C
Explanation
The correct answer is Option 3 i.e. 329.
Number - 9 is divisible by LCM of 64 and 80.
LCM(64, 80) = 320
So, Number = 320 + 9 = 329