SSC GD 2025 PYQ — Question 47

SSC GD Const 2025 (English) - 12 Feb 2025 - Shift 3 • Quantitative Aptitude • Q47

What is the smallest number which is when increased by 5 is divisible by 18, 30, 36 and 24?

Show answer & explanation

Correct answer: A

Explanation

The correct answer is option 1 i.e. 355.

LCM of (18, 30, 36, 24)

18 = 2 × 32

30 = 2 × 3 × 5

36 = 22 × 32

24 = 23 × 3

LCM = 23 × 32 × 5 = 360

So, number + 5 = 360

number = 355