What is the smallest number that, when divided by 2, 3, 4, 5, 6, and 7 leaves remainder 1?
Show answer & explanation
Correct answer: A
Explanation
If dividing the number by 2, 3, 4, 5, 6, and 7 leaves a remainder of 1 in each case, then
(Number − 1) will be completely divisible by 2, 3, 4, 5, 6, and 7.
LCM(2, 3, 4, 5, 6, 7) = 420
Therefore, the number = 420 + 1 = 421.