SSC CGL 2022 PYQ — Question 67

SSC CGL - 05 Dec 2022 - Shift 3 • Quantitative Aptitude • Q67

What is the smallest number that should be added to 4567 so that the sum is divisible by 7?

Show answer & explanation

Correct answer: D

Explanation

The correct answer is option 4 i.e. 4

Calculations:

When dividing 4567 by 7 , we get 3 as remainder

Hence, when dividing 3/7, we need to add 4 to the remainder such that it is divisible by 7

Therefore, the required number is 4.