What is the radius of the circle that circumscribes the triangle ABC whose sides are 16, 30, and 34 units, respectively?
Show answer & explanation
Correct answer: B
Explanation
The correct answer is Option 2 i.e. 17 units.
Dimension of the triangle = 16, 30, and 34
In △ABC
By Pythagoras theorem
⇒ AB2 = AC2 + BC2
⇒ 342 - 302 = AC2
⇒ AC2 = 1156 - 900
⇒ AC2 = 256 = 162
Hence, it is a right-angled triangle
The circumradius of a right-angled triangle = H/2 = 34/2 = 17 units