SSC CPO 2022 PYQ — Question 147

The correct answer is option 2 i.e. $1{{1} \over 5}$

Given that

$\begin{array}{l} \sqrt{36 \div 15 \text { of } 2 \text { of }[25 \times 4 \div 4 \text { of }\{29-(8-11) \div(9 \times 5 \div 5 \text { of } 3)\}]} \\ \end{array}$

⇒ $\begin{array}{l} \sqrt{36 \div 15 \text { of } 2 \text { of }[25 \times 4 \div 4 \text { of }\{29-(-3) \div(9 \times 5 \div 15)\}]} \\ \end{array}$

⇒ $\begin{array}{l} \sqrt{36 \div 15 \text { of } 2 \text { of }[25 \times 4 \div 4 \text { of }\{29 +3 \div(3)\}]} \\ \end{array}$

⇒ $\begin{array}{l} \sqrt{36 \div 15 \text { of } 2 \text { of }[25 \times 4 \div 4 \text { of }\{30\}]} \\ \end{array}$

⇒ $\begin{array}{l} \sqrt{36 \div 15 \text { of } 2 \text { of }[100\div 120]} \\ \end{array}$

⇒ $\begin{array}{l} \sqrt{[36 \div 3000/120]} \\ \end{array}$

⇒ $\begin{array}{l} \sqrt{[36/25]} \\ \end{array}$

⇒ 6/5 = $1{{1} \over 5}$