SSC CHSL 2025 PYQ — Question 62

SSC CHSL - 18 Nov 2025 - Shift 3 • Quantitative Aptitude • Q62

What is the least value that should be added to 1812 to make it divisible by 7, 11, and 14?

Show answer & explanation

Correct answer: B

Explanation

Given:

Number = 1812

Divisors = 7, 11, 14

Formula:

LCM(7, 11, 14) = 154

1812 divided by 154

1812 ÷ 154 = 11, remainder 118

Next multiple = 154 × 12 = 1848

Number to add = 1848 − 1812 = 36