What is the least number which when decreased by 7 is divisible by 15, 24, 28 and 32?
Show answer & explanation
Correct answer: B
Explanation
The correct answer is option 2 i.e. 10087
Solution :
The LCM of (15, 24, 28, 32) = 3360
Now, the required number = (3360 × n) + 7
Now putting the value of n according to the options,
n = 3
Required number = (3360 × 3) + 7 = 10087
the required number = 10087.