What is the lateral surface area of a pyramid whose base dimension is 12 m x 8 m and slant height is 18 m?
Show answer & explanation
Correct answer: C
Explanation
Given:
Base = 12 m × 8 m
Slant height = 18 m
By the formula:
Lateral surface area of the pyramid = 1/2 × perimeter of the base × slant height
Perimeter of the base = 2(12 + 8) = 40
Lateral surface area = 1/2 × 40 × 18 = 360 m²