What is the largest two digit number which when divided by 6 and 5 leaves remainder 1 in each case?
Show answer & explanation
Correct answer: C
Explanation
The correct answer is option 3 i.e. 91
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Understanding |
Application |
Calculation |
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First we need to get LCM of 5 and 6. |
LCM of 5 and 6 = 30 |
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Since the number is largest 2 digit number. |
Largest 2 digit number which is LCM of 5 and 6 = 90 |
⇒ 30 × 3 = 90 |
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Since the number when divided by 6 and 5 leaves remainder 1 in each case |
Required number = 91 |
⇒ 90 + 1 = 91 |