What is the largest two-digit number that is divisible by both 7 and 3?
Show answer & explanation
Correct answer: D
Explanation
The correct answer is option 4 i.e. 84.
We know that the largest two-digit number is 99.
A number that is to be divisible by 7 and 3, then the number should be divisible by LCM of (7, 3) i.e. 21.
Since 99 is not divisible by 21,
{(21 × 4) + 15}/21
Since 15 is the remainder,
So, subtracting 15 from 99 will give the number that is divisible by 21.
Hence the required number is 99 - 15 = 84.