SSC GD 2025 PYQ — Question 56

SSC GD Const 2025 (English) - 10 Feb 2025 - Shift 1 • Quantitative Aptitude • Q56

What is the highest number between 4000 and 5000, which when divided by 12, 16 and 24 would leave the remainder 4?

Show answer & explanation

Correct answer: D

Explanation

The correct answer is option 4 i.e. 4996.

Number leaves remainder 4 when divided by 12, 16, and 24

⇒ Number - 4 is divisible by LCM(12, 16, 24)

LCM of 12, 16, 24 = 48

So, number = 48k + 4

Find max number ≤ 5000:

48k + 4 ≤ 5000 ⇒ 48k ≤ 4996 ⇒ k = 104

Number = 48 × 104 + 4 = 4996