What is the greatest number of six digits, which when divided by each of 16, 24, 72, and 84, leaves the remainder 15?
Show answer & explanation
Correct answer: B
Explanation
The correct answer is option 2 i.e. 999951
Take LCM of 16, 24, 72 and 84 = 1008
Let the greatest six digits number = 999999
Now, 999999/1008 = Remainder 63
Then the greatest number = 999999 - 63 = 999936 which is completely divisible by 1008
But it leaves the remainder 15
Hence, the required six-digit number = 999936 + 15 = 999951