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SSC GD 2023 PYQ — Question 46

SSC GD Constable (English) - 12 Jan 2023 - Shift 3 (Set 1) • Quantitative Aptitude • Q46

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What is the faulty weight used by a dishonest shopkeeper instead of the original weight of 1 kg to get a profit of 25%?

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Correct answer: B

Explanation

The correct answer is Option 2 i.e. 800 grams.

Shopkeeper uses a faulty weight and gains 25% profit

Formula Used:

Percentage profit =error(Trueweight−error)×100 ={error\over(True weight-error)}\times100

Now,

Let the error be a grams

⇒ 25 = a/(1000 - a) × 100

⇒ 25(1000 - a) = 100a

⇒ 25000 - 25a = 100a

⇒ 25000 = 125a

⇒ a = 200

Hence, faulty weight = 1000 - 200 = 800 gm