SSC GD 2023 PYQ — Question 46

SSC GD Constable (English) - 12 Jan 2023 - Shift 3 (Set 2) • Quantitative Aptitude • Q46

What is the faulty weight used by a dishonest shopkeeper instead of the original weight of 1 kg to get a profit of 25%?

Show answer & explanation

Correct answer: B

Explanation

The correct answer is Option 2 i.e. 800 grams

Let the faulty weight be x grams

Given that

Original weight is 1000 grams

The profit % = 25%

Formula used 

Profit% =  [(Original weight - faulty weight)/faulty weight] × 100

According to the question

⇒  25 = [(1000 - x)/x] × 100

⇒ 0.25 = (1000/x) - 1

⇒ 1000/x = 1.25

⇒ x = 1000/1.25 = 800 grams