SSC Selection Post 2022 PYQ — Question 68

The correct answer is option 3 i.e. ₹663. 

$A = P \times \left(1+\frac{R}{100}\right)^n$

$A = 8,125 \times \left(1+\frac{4}{100}\right)^2$

A = 8125 × (1 + 0.04)²  = 8125 × (1.04)² = 8788 Rs

Compound Interest = A − P = 8788 - 8125 = Rs 663