SSC CGL 2025 PYQ — Question 53

The correct answer is option 1 i.e. 12π - 9$\sqrt{3}$.

Radius (r) = 6 cm, Angle at center (θ) = 120°

Sector area = (θ/360) × π × r²

= (120/360) × π × 6²

= (120/360) × π × 36

= 12π cm²

Triangle area = (1/2) × r² × sinθ

= (1/2) × 6² × sin 120°

= 18 × (√3/2)

= 9√3 cm²

Segment area = Sector area – Triangle area = 12π – 9√3 cm²