SSC CGL 2025 PYQ — Question 59

 The correct answer is option 1 i.e. $25 \pi$ cm².

Given, central angle = 90° 

And radius = 10 cm

Area of sector = $\frac{\theta}{360^0} \times \pi r^2$

⇒ $\frac{90}{360} \times \pi \times 10^2$

⇒ $\frac{100 \pi}{4}$ = $25 \pi$