SSC CHSL 2019 PYQ — Question 64

Concept

Understanding

Application

Diagonal of a rhombus bisect each other at right angle.

Area of rhombus = 1/2 × Digonal₁ × Diagonal₂

Given:

Side = 13 cm

Smaller diagonal = AC = 10 cm

Then OA = OC = 10/2 = 5 cm

In the figure;

AOB is right angle triangle:

OB = √(AB²– OA²)

OB = √(13² – 5²) = 12 cm

Hence,

BD = 2 ×  OB = 24 cm

Now,

Area of rhombus = 1/2 × AC × BD

= 1/2 × 10 × 24

= 120 cm²