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SSC Selection Post 2019 PYQ — Question 60

SSC Selection Post - Matriculation Level 2019 - 14 Oct 2019 - Shift 1 • Quantitative Aptitude • Q60

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 What is the area (in cm²) of a sector of a circle, with central angle 75°, when the diameter of the circle is 9 cm?
 

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Correct answer: D

Explanation

The correct answer is Option 4 i.e. 135π/32

Central angle θ = 75°

Diameter = 9 cm

⇒ Radius =9/2 = 4.5 cm

Area = θ360∘×πr2\frac{\theta}{360^\circ} \times \pi r^2 \\

=75360×π×(4.5)2=524×π×20.25= \frac{75}{360} \times \pi \times (4.5)^2 \\ = \frac{5}{24} \times \pi \times 20.25 \\

=101.2524π=13532π = \frac{101.25}{24} \pi = \frac{135}{32} \pi\