SSC CGL 2022 PYQ — Question 69

SSC CGL - 13 April 2022 - Shift 3 • Quantitative Aptitude • Q69

What is te value of p, if 25(3 + 4p) ÷ 12 of 5 - 3 × 8 = 6?

Show answer & explanation

Correct answer: D

Explanation

The correct answer is option 4 i.e.  1714\frac{1}{4}

Given :

25(3 + 4p) ÷ 12 of 5 - 3 × 8 = 6

Solution :

⇒ 25(3 + 4p) ÷ 12 of 5 - 3 × 8 = 6

⇒ 25(3 + 4p) ÷ 60 - 3 × 8 = 6

⇒ 25(3+4p)60−24=6{25(3 + 4p)\over 60} - 24 = 6

⇒ (1512+20p12)−24=6({15\over 12 }+ {20p\over 12}) - 24 = 6

⇒ (15+20p)12−24=6{(15 + 20p)\over 12} -24 = 6

⇒ (15+20p−288)12=6{(15 + 20p - 288)\over 12} = 6

⇒ 20p - 273 = 72

⇒ 20p = 72 + 273 

⇒ 20p = 345

⇒ p = 34520{345\over 20}

⇒ p = 171417\frac{1}{4}

Hence the value of p is 171417\frac{1}{4} .