What are the values of R and M, respectively, if the given number is perfectly divisible by 16 and 11 ?
34R05030M6
Show answer & explanation
Correct answer: C
Explanation
The correct answer is option 3 i.e. 5 and 5
Given a number
34R05030M6 is completely divisible of 16 and 11
The divisibility rule of 11 is that the difference between the sum of digits at even places and odd places is completely divided by 11 then we can say that number is divisible by 11.
(3 + R + 5 + 3 + M) - (4 + 0 + 0 + 0 + 6) = 11 + R + M - 10 = R + M + 1
Now this number is divided by 16 when it is divided by 2, 4, 8
The last 3 digit is divided by 8 and the last two digit divided by 4
hence the value of M should be 5 to satisfy this condition
M = 5
Now R + M + 1 = R + 6 is divide by 11 when R = 5
Thus R = 5, M = 5