SSC Selection Post 2024 PYQ — Question 56

SSC Selection Post - Higher Secondary Level - 21 June 2024 - Shift 2 • Quantitative Aptitude • Q56

Veena and Karmesh were at different places in Delhi. They fixed a meeting point to meet to settle some issue. Veena started her journey at 8:00 a.m. from place A and reached place B at 4:00 p.m. and Karmesh started moving from place B 2 hours later than the time Veena started and could reach place A at 5:00 p.m. the same day, via the same route. At what time will Karmesh and Veena meet each other?

Show answer & explanation

Correct answer: B

Explanation

The correct answer is Option 2 i.e.12:48 p.m.

Let total distance = D

Veena: 8:00 a.m. to 4:00 p.m. → 8 hours

Veena's speed = D/8

Karmesh: 10:00 a.m. to 5:00 p.m. → 7 hours

Karmesh's speed = D/7

Let they meet after t hours from 8:00 a.m.

Veena travels for t hours = D/8 × t

Karmesh starts at 10:00 a.m., so he travels for t−2 hours = D/7 × (t - 2)

D/8 × t + D/7 × (t - 2) = D

t/8 + (t - 2)/7 = 1

7t + 8(t - 2) = 56

7t + 8t - 16 = 56

15t = 72

t = 4.8 hours = 4 hours 48 minutes

So, they will meet at 12:48 pm