Two successive increases of 15% each, is by what percentage more than the two successive decreases of 12% each? (Rounded off to 2 decimal places)
Show answer & explanation
Correct answer: C
Explanation
The correct answer is option 3 i.e. 42.95%.
Assume initial value = 100
After first increase = 100 + 15% = 115
After second increase = 115 × 1.15 = 132.25
After first decrease = 100 − 12% = 88
After second decrease = 88 × 0.88 = 77.44
The total decrease = 100 - 77.44 = 22.56
The percentage decrease = (22.56 / 100) × 100 = 22.56%
The difference = 32.25% - 22.56% = 9.69
Percentage difference = (9.69 / 22.56) × 100 = 42.95%