Two parallel chords are drawn in a circle of diameter 20 cm. The length of one chord is 16 cm and the distance between the two chords is 12 cm. The length of the other chord is:
Show answer & explanation
Correct answer: C
Explanation
The correct answer is option 3 i.e 16 cm
| Understanding | Application |
| The perpendicular line on the chord in the circle bisects the chord. |
From the theorem ⇒ AC = BC, A'C' = B'C' In triangle ACO AC = 8 cm & CO = 6 cm By Pythagoras theorem AO = 10cm = Radius of circle In triangle A'C'O ⇒ OA' = 10 cm & C'O = 6 cm So A'C' = 8 cm A'B' = 2 × 8 = 16 cm |