Two numbers are in the ratio of 9 : 7. If the larger number is 56 more than one-seventh of the smaller, then what is the sum of the two numbers?
Show answer & explanation
Correct answer: C
Explanation
The correct answer is option 3 i.e. 112.
Let the 1st number and 2nd number be 7y and 9y
According to question,
9y - 7y × (1/7) = 56
⇒ 9y - y = 56
⇒ 8y = 56
⇒ y = 7
The sum of two numbers = 9 × 7 + 7 × 7
⇒ 112