Two numbers are in the ratio 5 : 6. If 16 is subtracted from each, the numbers will be in the ratio 3 : 4. If 8 is added to the first number and 3 is subtracted from the second, then they will be in the ratio:
Show answer & explanation
Correct answer: B
Explanation
The correct answer is option 2 i.e. 16 : 15.
Let the common ratio be x.
Two numbers are 5x and 6x.
ATQ -
(5x - 16)/(6x - 16) = 3/4
20x - 64 = 18x - 48
2x = 16
x = 8
5x = 5(8) = 40
6x = 6(8) = 48
40 + 8 = 48
48 - 3 = 45
Required ratio = 48 : 45 = 16 : 15