Two equal circles of radius 6 cm intersect each other such that each pass through the centre of the other. The length (in cm) of the common chord is:
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Correct answer: B
Explanation
The correct answer is option 2 i.e. 6.
OX = XY/2 = 6/2 = 3 cm
Radius (AX) = 6 cm
In ΔXAO, AO = √(AX2 - OX2) = √(62 - 32) = √(36 - 9) = √27 = 3√3 cm
AB = 2 × AO = 2 × 3√3 = 6√3 cm