Two equal circles intersect so that their centres, and the points at which they intersect form a square of side 1 cm. The area (in sq.cm) of the portion that is common to the circles is:
Show answer & explanation
Correct answer: B
Explanation
The correct answer is Option 2 i.e. (π/2 – 1)
|
Understanding |
Application |
|
Two equal circles intersect so that their centres, and the points at which they intersect form a square of side 1 cm. |
Square = AOBO’ Side of the square = 1 cm Area of the square = 1 cm Area of sector AOB = πr × 90/360 = π/4 Area of sector AO’B = πr × 90/360 = π/4 Hence, Area of the portion that is common to the circles = π/4 + π/4 – 1 = (π/2 – 1) |
