Two cyclists start toward each other from towns A and B, which are 150 km apart. Cyclist A leaves A at 6:00 a.m. with a speed of 20 km/h. Cyclist B leaves B at 7:00 a.m. and they meet at 9:00 a.m. Find the speed of cyclist B (in km/h), rounded to two decimals.
Show answer & explanation
Correct answer: D
Explanation
A's Speed = 20 km/h
A's Time = 6:00 to 9:00 = 3 hours
B's Time = 7:00 to 9:00 = 2 hours
Distance between A and B = 150 km
Distance covered by A = 20 × 3 = 60 km
Remaining distance = 150 − 60 = 90 km
B's Speed = 90 / 2 = 45.00 km/h