SSC MTS 2026 PYQ — Question 14

SSC MTS - 5 Feb 2026 - Shift 3 • Quantitative Aptitude • Q14

Two cyclists start at the same time from towns A and B, which are 210 km apart, and travel towards each other. The cyclist from A rides at 28 km/h, and the cyclist from B rides at 32 km/h. Find the time (in hours) taken by the cyclist from B to reach town A after meeting.

Show answer & explanation

Correct answer: A

Explanation

Given:

Distance between A and B = 210 km

Speed ​​of A = 28 km/h

Speed ​​of B = 32 km/h

According to the formula:

Time to meet = Total distance / (Sum of their speeds)

Time to meet = 210 / (28 + 32)

= 210 / 60

= 3.5 hours

Distance covered by A in 3.5 hours = 28 × 3.5 = 98 km

Remaining distance (to A) = 210 − 98 = 112 km

Time = Distance / Speed ​​= 98 / 32 = 3.06 hours