Two circles of radius 6 cm each. They intersect each other such that each passes through the centre of the other. What is the length of the common chord?
Show answer & explanation
Correct answer: C
Explanation
The correct answer is Option 3 i.e. 6√3 cm.
XO = XY/2 = 6/2 = 3 cm
AX = 6 cm [Radius]
In ΔXAO, AO = √(AX2 - XO2) = √(62 - 32) = √27 = 3√3 cm
Common chord (AB) = 2 × AO = 6√3 cm