SSC MTS 2026 PYQ — Question 1

SSC MTS - 20 Feb 2026 - Shift 1 • Quantitative Aptitude • Q1

Two chords AB and CD of a circle meet at a point P outside the circle. It is given that AP = 6 cm, BP = 3 cm, and CP = 4 cm. Find the length of PD.

Show answer & explanation

Correct answer: C

Explanation

Given:

AP = 6 cm, BP = 3 cm, CP = 4 cm

According to the formula:

For an external point: AP × BP = CP × PD

6 × 3 = 4 × PD

18 = 4PD

PD = 18 / 4 = 4.5 cm

PD = 4.5 cm