Two chords AB and CD of a circle with centre O intersect each other at P. If ∠BOC = 70o and ∠AOD = 100o, then ∠APC is:
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Correct answer: A
Explanation
The correct answer is option 1 i.e 60o

In the diagram given that,
⇒ ∠AOD = 100o
The sum of all angles subtended on a line is 180o
⇒ ∠AOD + ∠BOD = 180o
⇒ ∠BOD = 80o
In the triangle, OCD the sum of angles is 180o where angles ∠OCD & ∠ODC are equal, let call them 'x'
⇒ ∠ODC + ∠OCD + ∠COD = 180o
⇒ 2x = 30o
⇒ x = 15o
In the triangle, OCP the sum of angles,
⇒ ∠OCP + ∠OPC + ∠POC = 180o
⇒ 15o + ∠OPC + 70o = 180o
⇒ ∠OPC = 95o = ∠APC