Two chords AB and CD of a circle intersect at a point P inside the circle. If AP=5 cm, PB=8 cm, and CP=4 cm, what is the length of chord CD?
Show answer & explanation
Correct answer: B
Explanation
Given:
AP = 5 cm
PB = 8 cm
CP = 4 cm
By the formula:
AP × PB = CP × PD
5 × 8 = 4 × PD
40 = 4PD
PD = 10 cm
CD = CP + PD
CD = 4 + 10 = 14 cm