Two chords AB and CD of a circle when produced, meet at a point P outside the circle. If AB = 6 cm, PB = 5 cm, PD = 4 cm, then CD is equal to:
Show answer & explanation
Correct answer: C
Explanation
The correct answer is Option 3 i.e. 9.75 cm
|
Concept |
Understanding |
Application |
|
Ref. the figure: PB × PA = PD × PC |
Given, AB = 6 cm, PB = 5 cm, PD = 4 cm Let the length of CD be x, PA = 5 + 6 = 11 and PC = (4 + x) |
5 × 11 = 4 × (4 + x) ⇒ (4 + x) = 55/4 ⇒ (4 + x) = 13.75 ⇒ x = 9.75 cm |