Two chords AB and CD of a circle are produced to intersect each other at a point P outside the circle. If AB= 7 cm, BP = 4.2 cm and PD =2.8 cm, then the length of CD is:
Show answer & explanation
Correct answer: D
Explanation
The correct answer is Option 4 i.e 14 cm
We know that,
BP × AP = DP × CP
⇒ 4.2 × 11.2 = 2.8 × CP
⇒ CP = 16.8 cm
So,
CD = CP - DP
= 16.8 - 2.8 = 14 cm