Two alloys contain copper and zinc in the ratios 3:2 and 5:3. If equal masses of both are melted and mixed, what is the ratio of copper to zinc in the final alloy?
Show answer & explanation
Correct answer: C
Explanation
First mixture (Cu:Zn) = 3 : 2
Second mixture (Cu:Zn) = 5 : 3
The masses of both are equal.
First: Cu = 3/5, Zn = 2/5
Second: Cu = 5/8, Zn = 3/8
Total Cu = 3/5 + 5/8
(24 + 25)/40 = 49/40
Total Zn = 2/5 + 3/8
= (16 + 15)/40 = 31/40 ⇒ Ratio = 49 : 31