Triangle ABC is right angled at B. BD is an altitude intersecting AC at D. If AC = 9 and CD = 3 cm, then find the measures of AB (in cm).
Show answer & explanation
Correct answer: A
Explanation
The correct answer is option 1 i.e. 3√6
Let the length of BD be x.
AD = AC - CD = 9 - 3 = 6 cm
Applying Pythagoras theorem in ∆ABD -
AB2 = AD2 + BD2
AB2 = x2 + 36 ...(1
Applying Pythagoras theorem in ∆BCD -
BC2 = BD2 + CD2
BC2 = x2 + 9 ....(2
Applying Pythagoras theorem in ∆ABC -
AC2 = AB2 + BC2
92 = x2 + 36 + x2 + 9
2x2 = 36
x2 = 18
x = √18 = 3√2 cm
From eq(1 -
AB2 = x2 + 36
AB2 = (3√2)2 + 36 = 18 + 36 = 54
AB = 3√6 cm