SSC CGL 2021 PYQ — Question 54

SSC CGL - 20 Aug 2021 - Shift 1 • Quantitative Aptitude • Q54

Triangle ABC is an equilateral triangle. D and E are points on AB and AC respectively such that DE is parallel to BC and is equal to half the length of BC. If AD + CE + BC = 30 cm, then find the perimeter (in cm) of the quadrilateral BCED. 

Show answer & explanation

Correct answer: A

Explanation

The correct answer is option 1 i.e. 37.5.

DE || BC and DE = 1/2 × BC

It means that △\triangleADE is similar to △\triangleABC

one can say that △\triangleADE is also an equilateral triangle.

AD = AE and BD = CE.

AD + CE + BC = 30

AD + BD + BC = 30

AB + BC = 30

BC = 15

DE = 15/2 = 7.5

AB = BC = AC = 15

AD = 1/2 × AB = 15/2 = 7.5

Perimeter of BCED = 15 + 7.5 + 7.5 + 7.5 = 37.5.