SSC Selection Post 2020 PYQ — Question 71

SSC Selection Post - Matriculation Level 2020 - 10 Nov 2020 - Shift 1 • Quantitative Aptitude • Q71

Train X running at 50 km/h, leaves station a at 11 a.m., and train Y by running at 90 km on parallel tracks Leave station A at 3 p.m. on the same day and in the same direction. After what distance from station A will both the trains be together.

Show answer & explanation

Correct answer: D

Explanation

The correct answer is option 4 i.e. 450 Km.

Train X speed = 50 km/h

Train Y speed = 90 km/h

Train X leaves at 11 a.m.

Train Y leaves at 3 p.m.

Distance traveled by Train X = 50 km/h × 4 hours = 200 km

Relative speed  = 90 km/h − 50 km/h = 40 km/h

Time = Distance / Relative speed = 200 km / 40 km/h = 5 hours

Distance traveled by Train Y = 90 km/h × 5  hours = 450 km

Distance traveled by Train X = 50 km/h × 5 hours = 250 km

Total distance from station A = 200 km + 250 km = 450 km