To do a certain piece of work, A and B work alternately on alternate days, with B starting on the first day. A alone can finish the work in 22 days. If the work is finished in 11 1/2 days, then in how many days will B alone finish the 3/4 part of the original work?
Show answer & explanation
Correct answer: A
Explanation
The correct answer is option 1 i.e. 6 days.
A = 1/22, B = b
5 cycles + B + 1/2 A → 6b + 1/4 = 1 → b = 1/8
3/4 work by B = (3/4) ÷ (1/8) = 6 days