Three vessels X, Y, and Z hold liquid in the capacity ratio of 3 : 4 : 5. Each vessel contains a mixture of juice and water, where the proportions are 1 : 2 in X, 3 : 1 in Y, and 2 : 3 in Z. If the entire contents of these vessels are emptied into one large container and mixed uniformly, what will be the overall ratio of juice to water in the combined mixture?
Show answer & explanation
Correct answer: C
Explanation
Given:
Ratio of the capacities of the vessels = 3 : 4 : 5
Juice : Water
In X = 1 : 2
In Y = 3 : 1
In Z = 2 : 3
According to the formula:
Total Juice = (Juice part / Total parts) × Quantity
Total Water = (Water part / Total parts) × Quantity
Quantity of X = 3
Juice = (1/3) × 3 = 1
Water = (2/3) × 3 = 2
Quantity of Y = 4
Juice = (3/4) × 4 = 3
Water = (1/4) × 4 = 1
Quantity of Z = 5
Juice = (2/5) × 5 = 2
Water = (3/5) × 5 = 3
Total Juice = 1 + 3 + 2 = 6
Total Water = 2 + 1 + 3 = 6
Juice : Water = 6 : 6 = 1 : 1