Three solid metallic spheres of radii 1 cm, 6 cm and 8 cm, respectively, are melted and recast into a single solid sphere. The radius of the new sphere so formed is:
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Correct answer: A
Explanation
The correct answer is option 1 i.e. 9.0 cm.
the volume of a sphere is:
V = 4/3πr
where r is the radius of the sphere.
The volume of the first sphere (radius r1 = 1 cm):
V1 = 4/3π(1) = 4/3π cm
The volume of the second sphere (radius r2 = 6 cm):
V2 = 4/3π(6) = 288π cm
The volume of the third sphere (radius r3 = 8cm):
V3 = 4/3π(8) = 682.67π cm
the sum of the volumes of the three spheres = V1 + V2 + V3
= 4/3π + 288π + 682.67π = 972π cm
Let the radius of the new sphere be R.
The volume of the new sphere = 4/3πR
The volume of the new sphere = the sum of the volumes of the three spheres
4/3πR = 972π
R = = 729
R = = 9cm